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KEYMACRO is the final report of the Laboratory of Intelligent Systems, Graduate School of Electrical Engineering, Kyoto University. It is a customizable access control system and can be used in office or house (public and private).
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This Macro allows you to use your stored Certificate’s Private Key to digitally sign, and thus encrypt, the communication over a TLS 1.2 connection. The macro can decrypt, and thus decrypt, the TLS communication using your Certificate’s Public Key. When this Macro is used, the TLS 1.2 traffic is automatically authenticated by using the digital signature provided by the Macro. The Macro can be created using: CTRL+Shift+M. When it is used: CTRL+M.
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Prove that if $f$ is odd then $f(x) = 0$ for $x = \pi$

Prove that if $f$ is odd then $f(x) = 0$ for $x = \pi$
Suppose $f(x) = g(x)$ and $g(x)$ is even. Then $f(x) = -f(-x)$ but $-\pi = \pi$ so we have a contradiction.
Is this proof correct?


There is a much simpler proof. Let $f(x)$ be even, that is,


You can prove that if $f(x)$ is odd then $f(x)=0$ for $x=\pi$ in many ways, not only by using continuity. Here is a standard proof that’s easy to understand.
For $\alpha\in\mathbb R$, let $x_\alpha:=\pi+\alpha$. Then $x_\alpha=\alpha\pi$, so $x_\alpha\to\pi$ and $f(x_\alpha)\to f(\pi)$ as $\alpha\to0$. It follows that
f(\pi) = \lim_{\alpha\to0} f(x_\alpha) = \lim_{\alpha\to0}\lim_{\beta\to0}f(x_\alpha+\beta) = \lim_{\beta\